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Python Python Basics (2015) Shopping List App Break

Posted by Bill Tihen
Bill Tihen
17,790 Points

Challenge code Works on My Computer with python2 & python3

https://teamtreehouse.com/library/python-basics/shopping-list-app/break

def loopy(items): for item in items: if item == 'STOP': break print("* " + item) loopy(items)

[btihen@bt-laser:todo]$ python3 --version

Python 3.5.1

[btihen@bt-laser:todo]$ python --version

Python 2.7.11

[btihen@bt-laser:todo]$ python test.py

* tea

* bread

* dog food

[btihen@bt-laser:todo]$ python3 test.py

* tea

* bread

* dog food

MacOS - 10.11.3

breaks.py 
def loopy(items):
  for item in items:
    if item == 'STOP': break
    print("* " + item)
loopy(items)
# [btihen@bt-laser:todo]$ python3 --version
# Python 3.5.1
# [btihen@bt-laser:todo]$ python --version
# Python 2.7.11
# [btihen@bt-laser:todo]$ python test.py 
# * tea
# * bread
# * dog food
# [btihen@bt-laser:todo]$ python3 test.py 
# * tea
# * bread
# * dog food
# MacOS - 10.11.3

2 Answers

Dan Garrison
Dan Garrison
22,457 Points
Dan Garrison
Dan Garrison
22,457 Points

You should put your print in an else statement. Also, you only need your print to say print(item). You don't need the asterisk.

Bill Tihen
Bill Tihen
17,790 Points
Bill Tihen
Bill Tihen
17,790 Points

OK - I just figured if it breaks it terminates - otherwise the else happens without the else I removed the * & () too

def loopy(items): # Code goes here for item in items: if item == 'STOP': break else: print item

I still get -- bummer - somrthing's wrong, but it works on my computer still