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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Challenge error

My code works very well in python work space and gives results as accepted. But I am getting error in Challenge. Is there any issue with my code ?

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentence):
    dic={}
    lis = sentence.split(' ')
    for word in lis:
        num = lis.count(word)
        dic.update({word.lower():num})
    return dic

1 Answer

Steven Parker
Steven Parker
231,275 Points

Your external testing is likely not as rigorous as what the challenge does. But the "Bummer" message gave you a useful hint when it said "Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace" the argument to "split" should be left empty. Supplying a string literal argument with a space in it changes the behavior to split only on individual spaces.