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Python Python Collections (2016, retired 2019) Slices sillyCase

Posted by codelearnme
codelearnme
3,806 Points

Challenge sillycase, could use some help please!

So I tried it in my IDE of choice and it returns argumMENT however I see if I type a longer word when I call it, it obviously hard coded to stop at 4 maybe that's the mistake I'm not sure.. I even understand this challenge.! could someone help?

sillycase.py 
def sillycase(argument):
    arg2 = argument.lower()[0:5]
    arg3 = argument.upper()[4:]
    argument = arg2 + arg3
    return argument

2 Answers

Timm Derrickson
Timm Derrickson
21,205 Points
Timm Derrickson
Timm Derrickson
21,205 Points

The reason that you are having a problem is because you are using a static slicer. So, when you use [0:5] and [4:] it will only slice strings that are of length 8. To build a more dynamic slicer, I built a variable for the first half and the last half. Take a look at this example. 

half = int(len(string)/2)
first_half = string[:half].lower()
last_half = string[half:].upper()

I used the length of the string and divided it by two to get half of the message. I then used the int function to change the number from a float to a whole rounded down number. You can then put the variables into the slice itself. 

def sillycase(string):
    half = int(len(string)/2)
    first_half = string[:half].lower()
    last_half = string[half:].upper()
    return first_half + last_half
'''
codelearnme
codelearnme
3,806 Points

Thank you very awesome code :)

eg3
eg3
2,681 Points
eg3
eg3
2,681 Points

this worked for me...

def sillycase(i):
    half = int(round(len(i)/2))
    low = i[:half].lower()
    upp = i[half:].upper()
    return (low + upp)