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Kevin Duncan
510 PointsChallenge Task 1 of 1: If character at index 0.
Hello Team,
I'm trying to see where I'm going wrong with this. I did the "for" loop; then "if" for characters that are at index 0; then continue and print.
Thanks
def loopy(items): #"for" loop of characters in items for char in items:
#"if" the character at index 0 is 'a'; then continue
if char[0] == "a":
continue
#otherwise print current member else: print(char)
def loopy(items):
#"for" loop of characters in items
for char in items:
#"if" the character at index 0 is 'a'; then continue
if char[0] == "a":
continue
#otherwise print current member
else:
print(char)
2 Answers
Alexander Davison
65,469 PointsYour code is fine, it's just Python is picky about indentation. For example, this:
def loopy(items):
for char in items:
if char[0] == "a":
continue
else:
print(char)
Is way different than this (which is the solution to the challenge):
def loopy(items):
for char in items:
if char[0] == "a":
continue
else:
print(char)
You always need to indent your code properly or Python will cause an error :)
Good luck! ~alex
Kevin Duncan
510 PointsOhhh...Awesome!! I was about to pull my hair off my head...lol...Thanks Sir
Alexander Davison
65,469 PointsNo problem! :)