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JavaScript AJAX Basics (retiring) AJAX Concepts Finish the AJAX Request

Challenge Task 2 of 2 Add the code to send the AJAX request.

guys I am stuck please help

app.js
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
request.open("GET", "footer.html");
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

4 Answers

Michael Geatz
Michael Geatz
6,093 Points

You need to send a request to the server. Try adding this:

request.send();

var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
request.open("GET", "footer.html");
request.send(); <!-- this is where you need to place your code to send the AJAX request -->

if you opened the request, then send the request but without any parameters. Hope this helps

var request = new XMLHttpRequest(); request.onreadystatechange = function () { if (request.readyState === 4) { document.getElementById("footer").innerHTML = request.responseText; } }; request.open('GET', 'footer.html'); function sendAJAX() { request.send(); }

This is what I posted, but its asking "Did you call send() on the request object?" I thought that is what I did? Any suggestions?