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Brad Riebau
2,646 PointsChallenge Task 2 of 2 Add the code to send the AJAX request
Erghhhhh stuck can't figure out why this is not working! Help please!
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
request.open('GET', 'footer.html');
function requestOpen() {
request.open();
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
1 Answer
Julian Gutierrez
19,201 PointsVery close, you're just needing to send the request.
request.send();