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Start your free trialKurobe Kuro^T_T^
5,369 PointsChallenge Task 2 of 2 Now wrap it up by adding in __imul__, which does in-place multiplication. Be sure to update self.
i really dot get it
class NumString:
def __init__(self, value):
self.value = str(value)
def __str__(self):
return self.value
def __int__(self):
return int(self.value)
def __float__(self):
return float(self.value)
def __add__(self, other):
if '.' in self.value:
return float(self) + other
return int(self) + other
def __radd__(self, other):
return self + other
def __iadd__(self, other):
self.value = self + other
return self.value
def __mul__(self, other):
if "." in self.value:
return float(self) * other
return int(self) * other
def __rmul__(self, other):
return self * other
def __imul__(self, other):
self.value = self.value * other
return self.value
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsYou are close to having the correct answer. The goal of __imul__
is to retain the object type of self.value
as a str
.
Let's break down what you've tried:
def __imul__(self, other):
self.value = self.value * other
return self.value
Since self.value
is a string, multiplying it by a integer will result in a repeated string, not a new string containing the updated number. With the __mul__
method is available, use it to do the multiplication. To trigger the use of __mul__
, use self
as the multiplicand in place of self.value
. This gives us:
self.value = self * other
One drawback is __mul__
returns an integer instead of string. To fix this, wrap the multiplication with str()
:
self.value = str(self * other)
Post back if you need more help. Good luck!!
Kurobe Kuro^T_T^
5,369 PointsKurobe Kuro^T_T^
5,369 Pointsthank you id figure it out :D