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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Returning a Value from a Function

Posted by mo ode
mo ode
4,352 Points

Challenge Task 3. Call the getYear function: store the returned value of the function in a new variable named yearToday.

Challenge Task 3. Call the getYear function: store the returned value of the function in a new variable named yearToday. SHOW ME THE CODE. HELP.

script.js 
function getYear() {
var year = new Date().getFullYear();
  return year;
}
var yearToday
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Elijah Quesada
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Elijah Quesada
Front End Web Development Techdegree Graduate 32,965 Points
Elijah Quesada
.a{fill-rule:evenodd;}techdegree seal-36
Elijah Quesada
Front End Web Development Techdegree Graduate 32,965 Points

You were so close.

  1. Call the getYear function --> getYear();
  2. Store the return value in a new variable ---> var yearToday = getYear();
function getYear() {
var year = new Date().getFullYear();
  return year;
}
var yearToday = getYear();
mo ode
mo ode
4,352 Points

Thankyou very much. But what does the const mean? I don't remember that in the video. M(Thanks)

Elijah Quesada
.a{fill-rule:evenodd;}techdegree seal-36
Elijah Quesada
Front End Web Development Techdegree Graduate 32,965 Points

const is a E6 feature. You will learn about them as you continue to learn more about JavaScript.

https://teamtreehouse.com/library/introducing-es2015 - Treehouse has great content regarding the new features.

mo ode
mo ode
4,352 Points
mo ode
mo ode
4,352 Points

I completed part one, but part two makes no sense to me whatsoever. show me a diagram. And also the final 5 questions. Can you help? (Create a max() function challenge?)

Elijah Quesada
.a{fill-rule:evenodd;}techdegree seal-36
Elijah Quesada
Front End Web Development Techdegree Graduate 32,965 Points

I would like to. Just post the question under that challenge and I will get to it.