Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialMUZ140075 Melody A. Nyatsine
6,052 PointsChallenge Task 3 of 3 Finally, echo the following string inside of the if statement: 'Hi, I am Mike!'
whats wrong with my answer
<?php
$name = "Mike";
$name = "Mike"; if(name == "Mike")
{ echo = "Hi, I am Mike!"; }
?>
2 Answers
Julian Gutierrez
19,201 PointsA few things are wrong here, you've declared and assigned you variable correctly but you only need to do it once. I see it twice in your code. Your echo statement doesn't need the assignment operator/equal sign.
Eric Ewers
13,976 PointsYou are almost there. As said above, you only need to declare $name once and you don't need an equal sign with an echo statement. Also, I would suggest keeping your code formatted or indented so that you can read it more clearly.
$name = "Mike";
if ($name == "Mike") {
echo "Hi, I am Mike!";
}