Challenge task 3 of 4 of Teachers Stats

This one took some serious working through. First Task was tough but eventually deciphered it with some help from the forums and felt it was making sense. Second task was a breeze and the third one just stumped me. Finally got it working well in the workspace interpreter and then when I copied of=ver the code to the task window it gave me an error on TASK ONE!

had to take the whole thing back to the interpreter for debugging and finally sorted it out after modeling Task One after Task Three.

Anyway:

# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.

def most_classes(classes):
    teacher = ()
    count = 0
    high_count = 0
    high_teacher = ()

    for name, value in classes.items():
        new_teacher = name
        count = len(value)
        if count > high_count:
            high_count = count
            teacher = new_teacher
        else:
            high_count = high_count
            teacher = teacher

    return teacher

def num_teachers(teachers):
  teacher_count = 0
  for name in teachers:
    teacher_count += 1
  return teacher_count

def stats(teachers):
  num_classes = []
  for name, value in teachers.items():
    new_list = [name, len(value)]
    num_classes.append(new_list)
  return num_classes

Hello Mike.

The challenge does not want strings here; we need the compiler to output a list of lists.

I had a quick look at your code, and apart from the newString line it looks pretty close to a good one.

You already have the teacher, 'k' in your for loop and the classes: 'v'. I would suggest to use the len() method on this value and you would be good to go!

Make sure we get a list for every teacher though!

And let me know if you need more help.

PS: also note that dict is a keyword in python, it is better is you do not use it in cases like this).

Vittorio

hey could you explain the 3 challenges a bit more finding it hard to understand what is going on.

The for loop gets me all the time and enumeration (dont understand it at all) any help would be great

Hi I meant to ask how enumeration works in general not in the example . Thanks

Try this:

def stats(my_dict):
    y =[]
    for x in my_dict:
    z = []
    z.append('{}'.format(x))
    z.append(len(my_dict[x]))
    y.append(z)

    return y

This was challenging but finally got it..

def most_classes(my_dict): maximum = 0 teacher_name = "" for key in my_dict: if len(my_dict[key]) > maximum: maximum = len(my_dict[key]) teacher_name = key return teacher_name

def num_teachers(my_dict): return len(my_dict)

def stats(my_dict): list2 =[] for key, value in my_dict.items(): list1 = [key, len(my_dict[key])] list2.append(list1) return list2