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Yele X.
5,537 PointsChange the value in the flavor variable to cookie dough. Preview the code and make sure the message appears.
The prompt suggests that all that is necessary is to change the variable value to "cookiedough". Once I change the value, however, the challenge still fails.
Is there something I am missing?
<?php
$flavor = "cookiedough";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookiedough") {
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}
?>
3 Answers
Yele X.
5,537 PointsHere is the screenshot from after I change that value. As I said before, this code fails.
Kris Phelps
7,609 PointsI might be mistaken, but if I recall, the flavor should be "Cookie Dough"
Yele X.
5,537 PointsKris Phelps You were right. How silly. I just spelled it without the space because that's how it is in the pre-written code that is already provided.
omg.
Kris Phelps
7,609 PointsIt's all good. I'm glad I could help :-)