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Python Python Basics (2015) Number Game App Squared

Ricardo Ortega
Ricardo Ortega
7,167 Points
Posted by Ricardo Ortega
Ricardo Ortega
7,167 Points

Check again the challenge. with tests and I can not solve it!

This is my code and the console result in python (2.7) :

def squared(item): try: ret=item*item except TypeError: try: ret = int(item) except: return item*len(item) else: return ret+ret else: return ret

print(squared(5)) print(squared("2")) print(squared("tim")) print(squared(-1)) print(squared("-1"))

The results:

25 4 timtimtim 1 -2

What's wrong?

Thank you very much :-)

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(item):
    try:
        ret=item*item
    except TypeError:
        try:
            ret = int(item)
        except:
            return item*len(item) 
        else:
            return ret+ret
    else:
        return ret
Ricardo Ortega
Ricardo Ortega
7,167 Points
Ricardo Ortega
Ricardo Ortega
7,167 Points

Sorry the return when item is a string with only digits is return ret*ret instead ret+ret. I solved the challenge

1 Answer

Josh Keenan
Josh Keenan
20,315 Points
Josh Keenan
Josh Keenan
20,315 Points

Here's my solution, it's a ValueError! Also the else isn't needed.

def squared(num):
  try:
    return (int(num) ** 2)
  except ValueError:
    return (str(num) * len(num))
Josh Keenan
Josh Keenan
20,315 Points
Josh Keenan
Josh Keenan
20,315 Points

Firstly I try to convert the num parameter to an integer, if it fails I catch the ValueError and then make sure it is a string and return the string as many times as there are characters in it!

Converting to string in the case it was a float or another data type.

Ricardo Ortega
Ricardo Ortega
7,167 Points
Ricardo Ortega
Ricardo Ortega
7,167 Points

it's more simple. better solution :-)