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James Whiting
39,124 Pointschoice.random test?
Why doesn't this pass?
import random
def nchoices(n, t):
num = n + 1
times = t
output = []
my_range = list(range(num))
for time in list(range(times)):
my_random = random.choice(my_range)
output.append(my_random)
print (output)
nchoices(100,25)
2 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsThe challenge asks to pick random items from a iterable. The iterable can be any container such as a list, set, dict, string. I've updated your code to treat the "n" argument as a container.
import random
def nchoices(n, t):
'''Return t random item from iterable n'''
#num = n + 1
times = t
output = []
#my_range = list(range(num))
for time in list(range(times)):
my_random = random.choice(n) #<-- choose from n instead of my_range
output.append(my_random)
#print (output)
return output #<-- need to return instead of print
#nchoices(100,25) #<-- comment out.
This can be simplified. Using 'iterable' as more descriptive argument than 'n' and 'times' directly as the argument
import random
def nchoices(iterable, times):
'''Return random items from iterable'''
output = []
# range returns a list
for time in range(times):
output.append(random.choice(iterable)) #<-- can combine steps
return output
James Whiting
39,124 PointsI guess I was close, I think I read the question wrong or the question was not clear enough. Thanks for the clarity. Also, didn't now that range() is an actual list() type object. : ) Kool.
Chris Freeman
Treehouse Moderator 68,441 Pointsrange is actually a range type object that behaves like a list when iterated upon. Try help(range) in the python shell.