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Python Python Collections (Retired) Tuples Tuples With Functions

Vidhya Sagar
Vidhya Sagar
1,568 Points
Posted by Vidhya Sagar
Vidhya Sagar
1,568 Points

Code challange,COMPLETELY LOST.

I dont know where to start in this Tuples With Functions Code challenge.

combo([1, 2, 3], 'abc')

Output:

[(1, 'a'), (2, 'b'), (3, 'c')]

If you use .append(), you'll want to pass it a tuple of new values.

This is the question.Someone Please help.

3 Answers

Alexander Davison
Alexander Davison
65,469 Points

You can use the zip function for this.

Step-by-step instructions:

  • Define a method that takes two arguments.
  • Zip those two arguments.
  • Convert the zip object to a list and return the final result.

If you follow the instructions correctly, you should end up with this:

def combo(x, y):
    return list(zip(x, y))

Good luck! ~alex

Vidhya Sagar
Vidhya Sagar
1,568 Points
Vidhya Sagar
Vidhya Sagar
1,568 Points

Thanks a ton bro.:)

Alexander Davison
Alexander Davison
65,469 Points

No problem :)

Nathapong Narumitrekagarn
Nathapong Narumitrekagarn
1,663 Points
Nathapong Narumitrekagarn
Nathapong Narumitrekagarn
1,663 Points

Thank you!

But I don't believe that we have learned 'zip' yet at this point. Is there supposed to be a method where we use 'enumerate' or 'item' to complete the challenge?

Vidhya Sagar
Vidhya Sagar
1,568 Points
Vidhya Sagar
Vidhya Sagar
1,568 Points

Yes you can @Nathapong Narumitrekagarn. I was Stuck up for quite some time in this stage .See this code ,hope it satisfies you .

def combo(x,y):
    op=[]
    for idx1,val1 in enumerate(x):
        for idx2,val2 in enumerate(y):
            if idx1==idx2:
                temp_tuple=val1,val2
                op.append(temp_tuple)
    return op
Nathapong Narumitrekagarn
Nathapong Narumitrekagarn
1,663 Points
Nathapong Narumitrekagarn
Nathapong Narumitrekagarn
1,663 Points

Thank you so much! I'm happy to say that I've had the same idea (creating a tuple when the indices are a match!), but I didn't know how to separate the two indices and values apart as I kept using plain 'index' and 'value' for both sets of lists.

Cheers

gyorgyandorka
gyorgyandorka
13,811 Points

Vidhya: your version is unnecessarily complicated - you don't need to use another loop, since you get the index value for both items from the first loop. (That was the task: you are looking for the item in the second list/iterable which has the same index as idx1, so you can simply refer to it as list2[idx1], and there's your second item for the tuple.)

A more advanced thing, but you should always think twice before using double-nested loops in situations where you could use a single one, because their running time will grow much faster as the input size gets larger (their so-called time complexity will typically be quadratic instead of linear).

Also, the variable name temp_tuple might be unfortunate, since those tuples are not temporary ones whose values are only used inside the block - on the contrary, they are the ones that will actually end up on the output list, untouched.

This is a more concise implementation of your approach (of course, in a real-life situation, zip() would be the most "pythonic" solution, as mentioned above):

def combo(iterable1, iterable2):
    output_list = []
    for index, item in enumerate(iterable1):
        output_list.append((item, iterable2[index]))
    return output_list

Keep up the good work :)