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Start your free trialYusuf Diyab
2,485 PointsCode Challenge
The message in the final echo command only makes sense if your favorite flavor is the same as mine. Add a conditional around that final echo command that checks if the flavor variable has a value of "cookie dough." (Remember to choose carefully between using a single equal sign and a double equal sign in the check.) Preview the code and, if you have a different flavor, make sure the message disappears.
<?php
$flavor = "vanilla"
?>
<?php
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
?>
1 Answer
Michal Kurtulík
9,203 Points<?php
$flavor = "ice cream"; // 4 setp. change to "cookie dough"
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if($flavor == "cookie dough" )echo "<p>Randy's favorite flavor is $flavor, also!</p>";
?>
Yusuf Diyab
2,485 PointsYusuf Diyab
2,485 PointsIve figured it out, Thank You