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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Anne Whitman
Anne Whitman
964 Points

Code Challenge for iterating through dictionary

I can't figure out what I'm doing wrong.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(my_string):
    my_string = my_string.lower()
    my_list = my_string.split()
    my_dict = {}
    for word in my_list
        count = 0
        for word2 in my_list
            if word == word2
                count+=1
        my_dict[word] = count
    return my_dict
Adham Ali
Adham Ali
Courses Plus Student 1,112 Points

The name of the error?

Anne Whitman
Anne Whitman
964 Points

Unfortunately all I get is "Bummer, try again"

Anne Whitman
Anne Whitman
964 Points

Actually, nevermind. I don't know why I didn't think to do it earlier, but I threw it into a file on my computer and ran it locally and the issue was syntax. Forgot the ":" in the "for" and "if" statements. Wish the error messages were better on the challenges. Thank you for replying though!

Adham Ali
Adham Ali
Courses Plus Student 1,112 Points

Anytime! Just keep mind that "bummer" mean a typo or something in your code not a run-time error