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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Sanoj Amarasiri
Sanoj Amarasiri
1,877 Points
Posted by Sanoj Amarasiri
Sanoj Amarasiri
1,877 Points

Code challenge in dictionaries: wordcount

I tried this code and "Bummer : try again" appears I don't understand why. I ran it an output is correct. I checked online and importing counter doesn't work either. I cannot figure out any other way. Please someone help me to get through this. :(

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(text):
    list_1 = text.lower().split()
    count = 1
    index = 0
    refer = 1
    dict_1 = {}
    dict_2 = {}
    for word in list_1:
        newlist = list_1[refer:]
        if word in newlist:
            count += 1
            dict_1.update({word : count})
        else:
            count = 1
            dict_2.update({word : count})

        refer += 1
        index += 1
    dict_2.update(dict_1)
    return dict_2
Brennan White
Brennan White
11,646 Points
Brennan White
Brennan White
11,646 Points

Did you ever get this to work? I ran the code, too, and it seems to be working fine.

1 Answer

Sanoj Amarasiri
Sanoj Amarasiri
1,877 Points
Sanoj Amarasiri
Sanoj Amarasiri
1,877 Points

I figure out shorter way. It worked, This is it.

def word_count(text): dict_1 = {} new_list = text.lower().split() for word in new_list: dict_1[word] = new_list.count(word)

return(dict_1)