Treehouse | Community | The Console

✨ Earn college credits in Cybersecurity, JS, HTML, CSS and Python

AI can only take you so far. 🌟 Start with core skills in JavaScript, HTML, CSS, or Python. 🚀

Join the Treehouse affiliate program and earn 25% recurring commission!

New No-Code Track! 🚀start learning today!

🌟 Dreaming of a bright future? 🎓 Ask about the Treehouse Scholarship program! 🚀

✨ Earn college credits in Cybersecurity, JS, HTML, CSS and Python

AI can only take you so far. 🌟 Start with core skills in JavaScript, HTML, CSS, or Python. 🚀

Newest
- Newest
- Active
- Unanswered
- Featured
All Topics

Sailaja Pidikiti
104 Points
Use the log method on the console object to print out the name variable.

Posted on Apr 20, 2022 by Sailaja Pidikiti

Sailaja Pidikiti
104 Points
1 Answer
Jeremiah Marcos
4,091 Points
challenge task 2 of 3 sayingi didnt write a console in my code?

Posted on Dec 8, 2020 by Jeremiah Marcos

Jeremiah Marcos
4,091 Points
1 Answer
Evan Buschor
1,790 Points
I think this questions is bugged. Just try to complete it yourself and you will see.

Posted on Oct 19, 2020 by Evan Buschor

Evan Buschor
1,790 Points
2 Answers
Hasnain Shah
1,409 Points
Use the appropriate console method to print out the details object.

Posted on Jul 10, 2020 by Hasnain Shah

Hasnain Shah
1,409 Points
2 Answers
Gena Aivazian
16,574 Points
Im not sure what im doing wrong, i tried everything but i think there is a bug in this assignment

Posted on May 18, 2020 by Gena Aivazian

Gena Aivazian
16,574 Points
2 Answers
B V K Mahijendra
9,133 Points
Review the code in app.js. Use the log method on the console object to print out the name variable.

Posted on Apr 14, 2020 by B V K Mahijendra

B V K Mahijendra
9,133 Points
1 Answer
B V K Mahijendra
9,133 Points
Review the code in app.js. Use the log method on the console object to print out the name variable.

Posted on Apr 13, 2020 by B V K Mahijendra

B V K Mahijendra
9,133 Points
2 Answers
Monica Messaggi Kaya
4,272 Points
The error message is not relevant to the variables and what is asked on the exercise.

Posted on Feb 29, 2020 by Monica Messaggi Kaya

Monica Messaggi Kaya
4,272 Points
2 Answers
CHIRAG MUTREJA
Full Stack JavaScript Techdegree Student 33 Points
Review the code in app.js. Use the log method on the console object to print out the name variable.

Posted on May 28, 2019 by CHIRAG MUTREJA

CHIRAG MUTREJA
Full Stack JavaScript Techdegree Student 33 Points
1 Answer
Zach Fowler
815 Points
how do i do this?? i cant seem to figure it out

Posted on Nov 3, 2018 by Zach Fowler

Zach Fowler
815 Points
1 Answer
Julia Voss
9,334 Points
I think there is a bug in this task. This is my answer to question 2: console.dir(details); It says the answer is wrong.

Posted on Jun 12, 2018 by Julia Voss

Julia Voss
9,334 Points
2 Answers
Michael Borsari
50 Points
how do i pass name to the console log

Posted on May 31, 2018 by Michael Borsari

Michael Borsari
50 Points
2 Answers
Bruno Antonellini
7,168 Points
I receive an error saying I didn't write "console" anywhere on the script

Posted on May 20, 2018 by Bruno Antonellini

Bruno Antonellini
7,168 Points
1 Answer
Antonio Stuckey
2,287 Points
Review the code in app.js. Use the log method on the console object to print out the name variable.

Posted on May 8, 2018 by Antonio Stuckey

Antonio Stuckey
2,287 Points
1 Answer
Wendy Anderson-Burton
948 Points
error does not make sense

Posted on May 2, 2018 by Wendy Anderson-Burton

Wendy Anderson-Burton
948 Points
4 Answers
Prerna Jena
384 Points
Review the code

Posted on Feb 9, 2018 by Prerna Jena

Prerna Jena
384 Points
1 Answer
PHASEKA MALATJI
431 Points
something wrng here the console.dir functions is not evaluating

Posted on Nov 6, 2017 by PHASEKA MALATJI

PHASEKA MALATJI
431 Points
1 Answer
Douglas Ward
335 Points
console freeze on Node.js Basics course work space paused message. continue working button: no response.

Posted on Sep 6, 2017 by Douglas Ward

Douglas Ward
335 Points
0 Answers
Richard Brown
6,950 Points
Use the appropriate console method to print out the details object.

Posted on Jul 11, 2017 by Richard Brown

Richard Brown
6,950 Points
2 Answers
PLUS

ravishankersargunam
Courses Plus Student 467 Points
You didn't pass in the `name` variable in to the `log` method.

Posted on Feb 28, 2017 by ravishankersargunam

ravishankersargunam
Courses Plus Student 467 Points
1 Answer
PLUS

ravishankersargunam
Courses Plus Student 467 Points
console.log("Andrew");

Posted on Feb 28, 2017 by ravishankersargunam

ravishankersargunam
Courses Plus Student 467 Points
1 Answer
Yousef Marzouk
569 Points
on the first challenge in node.js it keeps telling me I am missing an ) after the argument list but i don't know why.

Posted on Feb 1, 2017 by Yousef Marzouk

Yousef Marzouk
569 Points
2 Answers

Posting to the forum is only allowed for members with active accounts.
Please sign in or sign up to post.