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Ed B
Courses Plus Student 3,973 PointsCode not working
This function works in Workspaces when I pass it a list, but it doesn't work for this challenge. Not sure what is wrong with it.
def loopy(items):
x = 0
while x < len(items):
if items[x] == "a":
x += 1
continue
else:
print(items[x])
x += 1
2 Answers
Cindy Lea
Courses Plus Student 6,497 PointsYou can do this using a for or if condition:
def loopy(items):
for item in items:
if item[0] == "a":
continue
else:
print(item)
'''
Steven Parker
231,007 PointsJeremy's point (and Cindy's) that more compact code could satisfy this challenge is valid, but it doesn't address your issue.
You're comparing each item with "a" instead of just the element at index 0.
Line 4 should probably be like this:
if items[x][0] == "a":
Other than that, your logic is sound, even if it's not the most compact. Don't worry, you'll pick those skills up with practice.
Jeremy Hill
29,567 PointsJeremy Hill
29,567 PointsThe code above is over complicated for what the challenge is wanting. You can do a for loop that loops through each item in items and then check to see if the first index is equal to the letter 'a' and then print if it's not.