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Python Python Basics (2015) Shopping List App Continue

Otto Beyer
Otto Beyer
5,096 Points
Posted by Otto Beyer
Otto Beyer
5,096 Points

Code solution doesn't seem to be working. Tested my solution in the Python shell and appears to work perfectly.

def loopy(items):
    # Code goes here
    for item in items:
      if item[0] == "a":
        continue
    print(item)

items = ['apple','pear'] loopy(items);

3 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,426 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,426 Points

So very close. Your print statement is not inside your for loop so it only prints once.

def loopy(items):
    # Code goes here
    for item in items:
      if item[0] == "a":
        continue
      print(item)  # <-- indent
Vittorio Somaschini
Vittorio Somaschini
33,371 Points
Vittorio Somaschini
Vittorio Somaschini
33,371 Points

Hello Otto.

I have edited your question with the code properly formatted now.

Talking about the issue you are having here, I see you are missing the "else" statement to cover the other case (where item[0] is not the letter a)

Vitto

Otto Beyer
Otto Beyer
5,096 Points
Otto Beyer
Otto Beyer
5,096 Points

Dear Chris and Vittorio,

Thank you for the feedback. I feel so silly not getting the indentation right. How green of me...

Apologies also for the quality of my question. I didn't realize that I was submitting the question to forum otherwise I would have framed in the appropriate structure.

Best regards Otto