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Start your free trialrob bert
5,041 PointsCode that appears to work doesn't
So, in task two the num_courses function seems to return 4 if i use the dict in the comment, which i assume is correct. but it doesnt pass the task.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(arg1):
count = 0
for items in arg1.keys():
count += 1
return count
def num_courses(arg1):
out = 0
for items in arg1.keys():
for v in items:
out += 1
return out
1 Answer
Alex Koumparos
Python Development Techdegree Student 36,887 PointsHi Rob,
The .keys()
method on an iterable will return a list of keys. So when you write:
for items in arg1.keys():
your for loop will iterate through ['Andrew Chalkley', 'Kenneth Love']
. Accordingly, during the first iteration of that loop, items
will have the value 'Andrew Chalkley'. Then when you do a for loop on 'Andrew Chalkley', it's going to iterate through the characters in 'Andrew Chalkley' and increment your counter every time you get a new character.
To correctly use the method you are trying to use, you would need to remember that your outer loop is going to be a series of keys. Then in your inner loop you can use that key to index back into the iterable to get the value. E.g.,:
for key in some_dictionary.keys():
for element in some_dictionary[key]:
print(element)
If this seems a bit long-winded, you're right. There is a better way, and that's to use .items()
instead of .keys()
.
With .items()
you get back a list of tuples where the first element in each tuple is the key and the second is the value. This means you can structure your for loop as follows:
for key, value in some_dictionary.items():
print(key)
print(value)
Hope this helps
Cheers
Alex