Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript AJAX Basics (retiring) AJAX and APIs Call the jQuery $.getJSON method

Austin Ward
Austin Ward
2,067 Points

Code won't validate. What am I doing wrong?

Rechecked spelling between parameters and variables and it appears to be good. The only thing I could think to change would be the location of where I call he AJAX request within the Doc.ready function but doubt this will make a difference. I am sure I am missing something obvious.

Thanks!

weather.js
$(document).ready(function() {

  var weatherAPI = 'http://api.openweathermap.org/data/2.5/weather';
  var data = {
    q : "Portland,OR",
    units : "metric"
  };
  function showWeather(weatherReport) {
    $('#temperature').text(weatherReport.main.temp);
  };

  $.getJSON(weatherAPI, data, showWeather(weatherReport));
});
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>What's the Weather Like?</title>
  <script src="jquery.js"></script>
  <script src="weather.js"></script>
</head>
<body>
  <div id="main">
    <h1>Current temperature: <span id="temperature"></span>&deg;</h1>
  </div>
</body>
</html>

1 Answer

Kelly von Borstel
Kelly von Borstel
28,880 Points

Hi, Austin. I don't think you need to pass an argument to the showWeather function.

$.getJSON(weatherAPI, data, showWeather);
Austin Ward
Austin Ward
2,067 Points

Awesome, thank you Kelly!