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Start your free trialChristian Rowden
2,278 PointsCode works but need direction regarding how to record it properly.
The code seems to work correctly in that it records the correct number...My real frustration lies in my limited ability to express myself in python thus far. How can I record a key in relation to the value that is recorded for max_value??
If I could just get a push in the right direction I would greatly appreciate it. I'm fighting the urge to look the answer up in the forums.
Thank you very much.
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(arg):
return len(arg)
def num_courses(arg):
return sum(len(v) for v in arg.values())
def courses(arg):
single_list = []
for v in arg.values():
for items in v:
single_list.append(items)
return single_list
def most_courses(arg):
new_dict = {}
max_value = 0
swap_value = 0
for v in arg.values():
for items in v:
swap_value += 1
if swap_value > max_value:
max_value = swap_value
swap_value = 0
return max_value
2 Answers
Christian Rowden
2,278 PointsNot really... This just looks horrific and extremely unpythonic but I don't know how to express my solutions that well yet in python.
So the code snippet at the bottom is unpacking and recording the max_value of each value if the iteration that follows is greater than the previous one. Now that I have the correct iteration stored in max_value, how to I associate the key that goes to that particular value?
Christian Rowden
2,278 PointsPlease disregard this.. I believe that I've come to a solution. I was getting tunnel vision on the d.values().
Younghoo Park
Courses Plus Student 1,046 PointsYounghoo Park
Courses Plus Student 1,046 PointsDo you want to create a dictionary that has a key and max_value? Could you please clarify it more?