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Courses Plus Student 1,617 Pointscollections challenge question
My return dictionary should be the same as the example, but why the checking system told me that I didn't get the correct output?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(sentence):
word_list = str(sentence).lower().split(" ")
result = {}
word_num = len(word_list)
for word in word_list:
count = 0
for word1 in word_list:
if word1 == word:
count+=1
result[word] = count
print(result)
return result
1 Answer
james south
Front End Web Development Techdegree Graduate 33,271 Pointsthe error tells you to split on all whitespace, but you are only splitting on the space character. there are other whitespace characters such as newline and tab. split on () instead of (" ").