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Python Python Collections (2016, retired 2019) Dictionaries Word Count

yunjun wu
PLUS
yunjun wu
Courses Plus Student 1,617 Points

collections challenge question

My return dictionary should be the same as the example, but why the checking system told me that I didn't get the correct output?

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(sentence):
    word_list = str(sentence).lower().split(" ")
    result = {}

    word_num = len(word_list)
    for word in word_list:
        count = 0
        for word1 in word_list:
            if word1 == word:
                count+=1
        result[word] = count

    print(result)
    return result

1 Answer

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

the error tells you to split on all whitespace, but you are only splitting on the space character. there are other whitespace characters such as newline and tab. split on () instead of (" ").