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Start your free trialSean Flanagan
33,235 PointsCombo
Hi.
Can anyone tell me please why this won't pass? The error message just says to try again.
Cheers
Sean
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(iterable_1, iterable_2):
tup_list = list(zip(iterable_1, iterable_2))
1 Answer
Alexander Davison
65,469 PointsClose, but you didn't return anything!
Try returning tup_list
like this:
def combo(iterable_1, iterable_2):
tup_list = list(zip(iterable_1, iterable_2))
return tup_list
Also, you can just return the value of tup_list
directly.
def combo(iterable_1, iterable_2):
return list(zip(iterable_1, iterable_2))
Good luck! ~alex
Sean Flanagan
33,235 PointsSean Flanagan
33,235 PointsHi Alex.
I admit I forgot to return tup_list. Your first solution paid off.
Thanks again.
Sean :-)