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Mohammed Ismail
7,190 PointsCombo
Hi Team,
Can someone provide me the alternative code for below without using any built in functions.
def combo(arg1,arg2): tuple_list= list() arg3=zip(arg1,arg2) for element in arg3: tuple_list.append(element) return tuple_list
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
def combo(arg1,arg2):
tuple_list= list()
arg3=zip(arg1,arg2)
for element in arg3:
tuple_list.append(element)
return tuple_list
#print(combo([1, 2, 3],[2,5,6]))
2 Answers
Cody Kaup
14,407 PointsSince both arguments are the same length, we can loop through one argument and gather the index we're on with enumerate(). Something like this:
def combo(arg1, arg2):
tuple_list = list()
for index, element in enumerate(arg1):
tuple_list.append((arg1[index], arg2[index]))
return tuple_list
Mohammed Ismail
7,190 PointsThanks for clarifying Chris!!!
Mohammed Ismail
7,190 PointsMohammed Ismail
7,190 PointsThanks for your reply. I have an additional question, does .append() takes two argument. From my understanding, it restricts to 1. Please confirm.
Chris Freeman
Treehouse Moderator 68,441 PointsChris Freeman
Treehouse Moderator 68,441 PointsThe method
append()takes exactly one argument. The this case, the argument is a single tuple containing two items.