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Frank Sherlotti
Courses Plus Student 1,952 PointsCombo challenge, need some explanation please.
QUESTION: --- Create a function named combo() that takes two iterables and returns a list of tuples. Each tuple should hold the first item in each list, then the second set, then the third, and so on. Assume the iterables will be the same length. ----- My main question here is how does the enumerate() method work? I've watched the prior videos a few times now and nothing seems to want to click in my head. I was just looking for someone to maybe explain it a little more. And also it says it takes 2 iterables, does that mean the same thing as an argument? Silly question but I figured i'd ask it anyways considering I should probably know the answer already by now. All help is greatly appreciated!(:
# combo(['swallow', 'snake', 'parrot'], 'abc')
# Output:
# [('swallow', 'a'), ('snake', 'b'), ('parrot', 'c')]
# If you use list.append(), you'll want to pass it a tuple of new values.
# Using enumerate() here can save you a variable or two.
def combo(first, second):
for index, value in enumerate(first, second):
1 Answer
Mari Johannessen
12,232 PointsThe enumerate() function adds a counter to an iterable. It's one of the built-in Python functions. It returns an enumerate object. It allows you to create a for loop where you’re iterating over a sequence (list, tuple, etc) and have both the item and it's index in the loop. 2 iterables in this example means that you're iterating over two items, and that both the first and the second item and their indexes will be in the loop. Hopefully that makes a bit more sense, good luck! :)
Frank Sherlotti
Courses Plus Student 1,952 PointsFrank Sherlotti
Courses Plus Student 1,952 PointsReally appreciate the help!