Combo() Function That Returns List of Tuples

Question

The error message I received was "Where's 'combo()'?" I've deleted the lines of code to see if I could isolate an error in one of the other lines, but the error messages didn't lead me anywhere.
```zippy.py
combo([1, 2, 3], 'abc')
Output:
[(1, 'a'), (2, 'b'), (3, 'c')]
If you use .append(), you'll want to pass it a tuple of new values.
def combo(list1, list2):
for item in list1:
    my_tuples_list.append(list1[item], list2[item])

return my_tuples_list
```

Kourosh Raeen · Accepted Answer

Hi @matildadigital (https://teamtreehouse.com/matildadigital) - Before starting the for loop define the list:
python
my_tuples_list = []

That will take care of the "Where's combo()?" error. But there are other issues with the code. The loop variable item holds the items in list1, but you're using it as in index for both lists. Try changing your loop to:
python
for index in range(len(list1)):

Now you can use index as an actual index of items in both lists.
Last issue is that you need to return a list of tuples so before doing the append use parenthesis to make a tuple out of the two items and then append the tuple to my_tuples_list.

jcorum · Answer

matilda, yes, the error seems totally spurious.  Here, try this:
python
def combo(iter1, iter2):
  combo_list = []
  for index, value in enumerate(iter1):
    tuple = value, iter2[index]
    combo_list.append(tuple)
  return combo_list

Welcome to the Treehouse Community

Looking to learn something new?

matildadigital

matildadigital

Combo() Function That Returns List of Tuples

2 Answers

Kourosh Raeen

Kourosh Raeen

jcorum

jcorum

darcyprice

darcyprice