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Python Python Collections (2016, retired 2019) Sets Set Math

Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points

Common courses challenge

Here's my code. Any advice? Thanks!

sets.py
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}

def covers(topics):
    common_list=[]
    for subject in COURSES:
        common_subject=topics.intersection(subject)
        common_list.append(common_subject)
    return common_list

1 Answer

Jeff Muday
MOD
Jeff Muday
Treehouse Moderator 28,722 Points

Your approach definitely shows you know something about Python sets. Let's build on that.

  • I see you wanted common_list to be all courses matching your topics set.

Great idea, keep it.

  • You iterate through the COURSES set with a "for" loop.

Keep this idea-- but let's mod it slightly.

modification: you will want to use the COURSES.items() iterator. It's not the only way to do things, but it is advantageous because it returns BOTH the course_name and the course_topics. This is an important pattern Kenneth would like you to remember.

  • I like that you look for an intersection of topics -- well played, but let's change it a little.

modification: look for an intersection with course_topics instead.

  • I like you are doing the common_list.append. This is good, but we need to change it a little.

modification: Let's change it to ONLY append the course name when the length of the common_subject is greater than zero (which indicates our topics matched/intersected with course_topics. This will avoid us having empty sets appended to our list.

  • After the loop you return the common list. Well played, this is right.
def covers(topics):
    common_list=[]
    for course_name, course_topics in COURSES.items():
        common_subject=topics.intersection(course_topics)
        if len(common_subject) > 0:
            common_list.append(course_name)
    return common_list

Good luck on your Python journey. It can be a little frustrating at times, but pays off well!