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Python Python Basics (2015) Letter Game App Even or Odd Loop

John Paul Masters
John Paul Masters
1,722 Points
Posted by John Paul Masters
John Paul Masters
1,722 Points

Communication Problem

I have been trying to submit the last task, but it always stalls out and says there was a communication problem. I can't finish the task, I don't know why it is doing this

even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start:
    num = random.randint(1, 99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
start -= 1

2 Answers

reanimator313
reanimator313
6,005 Points

Your while loop has no end. That gives that error. Just indent start -= 1 insede the loop.

reanimator313
reanimator313
6,005 Points

I tried this code and it works

while start:
    num = random.randint(1, 99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
    start -= 1 # indented in the loop
Jay Padzensky
Jay Padzensky
4,731 Points
Jay Padzensky
Jay Padzensky
4,731 Points

Hey John Paul,

Occasionally, code input can be the source of a communication error. I ran your code on my end and received the same error.

I noticed that your start decrement is outside your while loop. Perhaps take a peek at that? Good luck, keep up the hard work!