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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by Andrei Li
Andrei Li
34,475 Points

Completely lost. Challenge Task 1 of 1.

Can you help with a challenge? Everything looks fine but it's not working. Thank you in advance.

disemvowel.py 
def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u"]
    position = 0
    for letter in list(word):
        for vowel in vowels:
            if letter == vowel:
                list(word).remove(vowel)

    position = +1

    return word

1 Answer

Wade Williams
Wade Williams
24,476 Points
Wade Williams
Wade Williams
24,476 Points

Few things, when using a for loop in python you don't need to keep a "position" variable, so let's remove that. By default a for loop will go through each character of a string, so no need to turn it into a list. We can do this in one loop, so let's get rid of the vowels for loop.

Your code has a lot going on, so let's describe the algorithm then code it up.

  1. Create a data structure to hold our vowels (Uppercase and Lowercase)
  2. Create a variable that will hold our result
  3. Loop through each character in word, if it's not a vowel then add it to our result
  4. return result
def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    result = ""

    for char in word:
        if char not in vowels:
            result += char

    return result
Andrei Li
Andrei Li
34,475 Points

Thank you! Very interesting construction.