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Start your free trialphillip parker
10,673 PointsConcatenation of the working variables. Why?
Can someone explain why there needs to be concatenation on each side of the working variable? What purpose does it serve?
Why won't this work?
echo '<img src="'$product["img"]'" alt="'$product["name"]'"';
Just curious. Thanks!
1 Answer
Chris Shaw
26,676 PointsHi Phillip,
Your current code is almost correct, after the opening single quote and before the ending single quote you need a period which tells the PHP compiler that you're joining two strings together, see the below.
NOTE: I've also added an ending closing bracket for the img
element.
echo '<img src="' . $product["img"] . '" alt="' . $product["name"] . '">';
Now your code should work without any issues.
Happy coding!
phillip parker
10,673 Pointsphillip parker
10,673 PointsHi Chris,
I don't think you understood my question exactly, but I think you answered it anyway. The way that I understand it is that the single quotes are treating the HTML elements like a strings and the concatenation is joining the working PHP variable (which becomes a string) to HTML strings, which is why the working variables must be concatenated.
Chris Shaw
26,676 PointsChris Shaw
26,676 PointsSorry, yes I did misunderstand slightly and yes that is what's happening, you can also include variables within strings using interpolation as well which is slightly cleaner but for most devs whom are new to PHP is harder to understand.
echo "<img src=\"{$product['img']}\" alt=\"{$product['name']\">";
One major different you will see if I've escaped the double quotes as PHP's version of interpolation requires double quotes to be surrounding the entire string, the other difference is instead of using double quotes to get the values in the
$product
array I've used single quotes as you can reuse double quotes if you're using interpolation.Hope that helps.