conditional php

Your conditional looks correct. However it looks like you already have a php tag open at the very start of your code so you dont need to open a new set of php tags around your conditional which could be causing some issues.

<?php
$flavor = "vanilla";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
<?php if ($flavor == "cookie dough") { echo "Randy's favorite flavor is cookie dough, also!"; } ?>

try removing the php tags around your condition and see if it works

//opening tag
<?php
$flavor = "vanilla";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if ($flavor == "cookie dough") { echo "Randy's favorite flavor is cookie dough, also!"; }

//closing tag
?>

Okay, that worked, but then when I went to the next step, it is saying that step 3 is not working (when I change favorite variable to cookie dough). Code is on bottom. Please advise Thank you

<?php $flavor = "cookie dough";

echo "<p>Your favorite flavor of ice cream is "; echo $flavor; echo ".</p>"; if ($flavor == "cookie dough") { echo "Randy's favorite flavor is cookie dough, also!"; }

?>

Hi Edward,

I noticed that in the code you are providing the html tags are missing. Did you pass any of the code challenges that way? Anyhow, here is the correct code for the code challenge:

<?php
$flavor = "cookie dough";

echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
if( $flavor == "cookie dough") {
  echo "<p>Randy's favorite flavor is cookie dough, also!</p>";
}

?>