Confused

Whoops..

This is the question the code challenge asks;

Write the code inside this mimic_array_sum() function. That code should add up all individual numbers in the array and return the sum. You’ll need to use a foreach command to loop through the argument array, a working variable to keep the running total, and a return command to send the sum back to the main code.

this is what I have and it appears to be incorrect;

<?php 


function mimic_array_sum($array) {
  $sum = 0;
    foreach($array as $number) {
    $sum = $sum + $number;
    }
  return $number;
}


$palindromic_primes = array(11, 757, 16361);
$total = mimic_array_sum($palindromic_primes);

?>

Ah I see, thank you for all the advice, I have been on the site few months but haven't used the forum yet, your help is appreciated

<?php

function mimic_array_sum($array) { 
  $sum = 0; foreach($array as $number) { 
    $sum = $sum + $number; 
  } 
  return $number; 
}

$palindromic_primes = array(11, 757, 16361); 
$total = mimic_array_sum($palindromic_primes);

echo $total;

?>

Hi Chase,

You have one thing wrong:

<?php
function mimic_array_sum($array) { 
  $sum = 0; foreach($array as $number) { 
    $sum = $sum + $number; 
  } 
  return $number; 
}
?>

In the above code you are returning the $number but the function is adding $sum + $number and placing that result into $sum.

So you should have $sum as the return.

Without checking I assume the current result would only return the last number in the array 16361.

The below code should solve your problem, it is easy to overlook.

<?php
function mimic_array_sum($array) { 
    $sum = 0; 
          foreach($array as $number) { 
          $sum = $sum + $number; 
  } 
  return $sum; 
}

?>

Hope this helps.

Robert Walker's answer is correct, but it's good to note that $number here is a local variable to the foreach function. You would probably get an error if you tried to return it from the mimic_array_sum function since it doesn't exist outside of the foreach.