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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Aaron Mesh
Aaron Mesh
1,001 Points

Confused about the error issue?

setup

Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

There Error message I'm getting is "Wrong number of prints". But the problems say to print for even and then print again for odds. am I getting this error because all of this is in a while loop and it just keeps printing continuously? If so how can I fix this? Do i just need to add a "continue" under the print statements?

even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start == True:
    rnum = random.randint(1, 99)
    if even_odd(rnum) == True:
        print("{} is even".format(rnum))
    else:
        print("{} is odd".format(rnum))
    start -= 1

1 Answer

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

I found that if you remove the == True part of the while condition will fix the case.

This is because start is truthy, not true itself. When you compare a plain old number with a boolean, they are always different. But since start is truthy, it will be treated as true when you just use it itself as a condition.

I know it is a little confusing... I used to get so frustrated on this too :)

I hope you understand. If you got any questions, please ask below :smile:

~Alex

Aaron Mesh
Aaron Mesh
1,001 Points

So it should look like 'while start = true"? Because I tried that and got a new error saying task 1 is no longer being completed

Alexander Davison
Alexander Davison
65,469 Points

It should be just while start. I know it's weird :)

Here's the right code:

even.py 
import random

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start = 5
while start:
    rnum = random.randint(1, 99)
    if even_odd(rnum) == True:
        print("{} is even".format(rnum))
    else:
        print("{} is odd".format(rnum))
    start -= 1