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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

Michael LaCroix
Michael LaCroix
5,828 Points

Confused by directions

I can't enter String as a parameter without getting an error message. I'm doing something wrong and can't figure out what.

The error hint at this point says Make sure you set the 'type' for mSpaceship as specified in the instructions. One small problem - I don't see where that is in the instructions. Obviously it's not explicit but I had no clue that's what I was supposed to be doing so apparently I'm totally lost.

LandingActivity.java
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class LandingActivity extends Activity {

    public Button mThrustButton;
    public TextView mTypeLabel;
    public EditText mPassengersField;

    public Spaceship mSpaceship;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_landing);

        mThrustButton = (Button)findViewById(R.id.thrustButton);
        mTypeLabel = (TextView)findViewById(R.id.typeTextView);
        mPassengersField = (EditText)findViewById(R.id.passengersEditText);

        // Add your code here!
      mSpaceship = new Spaceship(){

       };
    }
}
Spaceship.java
public class Spaceship {
    private String mType;
    private int mNumPassengers = 0;

    public String getType() {
      return mType;
    }

    public void setType(String type) {
      mType = type;
    }

    public int getNumPassengers() {
      return mNumPassengers;
    }

    public void setNumPassengers(int numPassengers) {
      mNumPassengers = numPassengers;
    }

    public Spaceship() {
      mType = "SHUTTLE";
    }

    public Spaceship(String type) {
      mType = type;
    }
}

1 Answer

Harry James
Harry James
14,780 Points

Hey Michael!

You need to pass in "FIREFLY" as the parameter for the constructor and then the challenge will pass.


I do agree that this error message could confuse users though so, I'm going to tag Ben Jakuben here to take this as feedback.

Some students may not look in the Spaceship class to see that it takes in a String which is referred to as the type in the constructor so, perhaps the error message should say something like

"Make sure you set the parameter for the Spaceship constructor as specified in the instructions."

as otherwise, some students may not know what is meant by the type.