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Start your free trialDevon Thompson
4,301 PointsConsole.log Loops
I'm not sure what I am doing wrong. It states that only 11 numbers were logged and I know it's probably an easy fix but I'm not sure what to do. Help, please!
for ( var i = 2; i >= 2 && i < 24; i += 2) { console.log(); }
for ( var i = 2; i >= 2 && i < 24; i += 2) {
console.log();
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
behar
10,799 PointsYou should be console.log(i). And the reason its only printning 11 numbers is because you told the loop to stop When i is 24, but you want to log 24, so change it to i < 25 or i <= 24. Hope this helps!
zainsra7
3,237 PointsLet's try to understand this with a simple example first:
Print/log numbers from 1 to 10 using for loop?
for( var i = 1 ; i <=10 ; i++) {
console.log(i);
}
A for loop has 3 parts :
- Initialization of counter variable (i) // We do this only at the start of for loop i = 1;
- Check condition of loop , i < = 10 that is execute for loop body till counter variable is less than or equal to 10. Or in other words stop executing loop once counter variable becomes 11.
- Increment counter variable. i ++ in this case increment by 1 , like 1 , 2 , 3 ,4 , 5 till 10.
Now in your problem, you need to print numbers from 2 to 24 and you already know how to print numbers from 1 to 10 so use the same strategy:
- Initialize counter variable with 2
- As you need to cover all even numbers smaller than 24 and also including 24 so you will use , while i <=24 or i != 26
- As you need to print even numbers like 2,4,6,8,10 ... so you will increment by 2 which is i+=2 or i = i + 2;
Final Solution :
for( var i = 2; i < = 24 ; i +=2){
console.log(i);
}
OR
for( var i = 2; i != 26 ; i +=2){
console.log(i);
}
why 26 tho ? I'll leave that for you to figure out :)
I hope it clears your question , Happy Coding !