continue problem

Question

def loopy(items):
    # Code goes here
    for item in items:
        if items[0] == "a": 
           if item == 0:
              continue
        else:
            print(items[item])
loopy(items)
breaks.py
def loopy(items):
    # Code goes here
    for item in items:
        if items[0] == "a" && item == 0
         continue
        else:
            print(items[item])

Jennifer Nordell · Answer

Hi there, Ted!  You've got a couple of problems here.  First, you're missing a colon to denote the beginning of a code block.  Secondly, your indentation is a little off.  Third, we want to evaluate the first letter of item, not items.  Let's say for example that the items being sent in looked like this ['apple', 'lemon', 'kiwi', 'orange'].  We want to print out every item that doesn't start with "a".
```python
def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)
```
Here, we're accepting our items list (that Treehouse is sending us).  Now for every item in items we need to evaluate  it to see if the first letter is "a".  If it is, we skip it.  Otherwise, we print it out.  Hope this helps! :sparkles:

Welcome to the Treehouse Community

Looking to learn something new?

Ted Hayali

Ted Hayali

continue problem

1 Answer

Jennifer Nordell

Jennifer Nordell