continue problem

This task does not require you to use continue (which skips an item), but break (which stops the loop), that is not actually the main problem with your code though, there are three big problems I can see right away:

1. You don't quite understand how for in loops work.

2. You are (trying to) compare all of the items to the letter "a", which is not what the task is asking you to do.

3. You create an index variable to access the items but you don't actually use it, (you hardcoded 0 as the index) and you don't increase the index within the loop either.

In a for in loop each item in a list is assigned to a variable inside of the loop (in your code you named the variable item, and the list is items) the first time though the loop the first object in the items list will be assigned to item, the second time though the loop the second object will be assigned to item, and so on.

Here is an illustration of how that works:

nameList = ["Tom", "Andy", "Peter", "Mona", "Lisa", "Elizabeth"]

for name in nameList:
    print("Hello there " + name)

'''
The above code will generate this:
Hello there Tom
Hello there Andy
Hello there Peter
Hello there Mona
Hello there Lisa
Hello there Elizabeth
'''

So as you can see each name in the nameList was passed in to the code block and executed, once the loop had gone through all of the items it exits automatically. This means that you don't actually need to create or update an index variable manually.

The challenge request that when an item contains the string "STOP" that you should end the loop entirely, as I said above this require you to use the keyword break, not the keywoard continue, it also requires you to compare items to the string "STOP" not to the string "a" which you are doing in the above code.

The solution looks like this:

def loopy(items):
    for item in items:
        if item == "STOP":
            break
        else:
            print(item)

It should also be noted that the challenge only asks you to complete the function, not to call it as well, doing that will actually cause the challenge to fail, even if the function's code is correct.