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Python Python Basics (2015) Shopping List App Continue

Posted by Aryan Monga
Aryan Monga
4,061 Points

Conversion error in python!

The question is " My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz". "

Whenever i try to run the code, an error is displayed " cannot convert 'int' to 'str' implicitly" I've understood the error but i'm just unable to find the answer! Please help me to edit the code! ;)

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if item.index(0) == 'a':
            continue
        else:
            print(item)

1 Answer

Thomas Fildes
Thomas Fildes
22,687 Points
Thomas Fildes
Thomas Fildes
22,687 Points

Hi Aryan.

Please see the below code that I used to pass this challenge:

def loopy(items):
    # Code goes here
    for item in items:
        if item[0] == "a":
            continue
        else:
            print(item)

Happy Coding!!!

Aryan Monga
Aryan Monga
4,061 Points

Thank you soooooo much!!!! ;)