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Python Python Basics (2015) Number Game App Squared

Posted by Jessica Barron
Jessica Barron
1,215 Points

Could someone please help explain what they think I am not understanding from this.

Please help explain what is wrong with the current code as well as how the 'working' code works.

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(var):
    var = 5
    try:
        return int(var) ** 2
    except var:
        return item * len(item)

1 Answer

Ioannis Leontiadis
Ioannis Leontiadis
9,828 Points
Ioannis Leontiadis
Ioannis Leontiadis
9,828 Points

Hello Jessica,

first of all the argument called var is assigned a value of 5 inside the function so the function always return the value of 25. You should remove that assigning statement.

Also, the try-except statement should be revised. The basic syntax is,

try:
    #code here
except Error:
    #code here

You should use ValueError in the place of Error for this problem.

Hope that helped!