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Python Python Collections (Retired) Dictionaries String Formatting with Dictionaries

Bentley Thompson
Bentley Thompson
13,287 Points
Posted by Bentley Thompson
Bentley Thompson
13,287 Points

Could you tell me what is wrong with this code? It runs in my Workspace but is giving me an error in the exercise window

dicts = [ {'name': 'Michelangelo', 'food': 'PIZZA'}, {'name': 'Garfield', 'food': 'lasanga'}, {'name': 'Walter', 'food': 'pancakes'}, {'name': 'Galactus', 'food': 'worlds'} ]

string = "Hi, I'm {} and I love to eat {}!"

def string_factory(thedicts, astring): alist = [] for eachdict in thedicts: alist.append(string.format(eachdict['name'], eachdict['food'])) return alist

strings.py 
dicts = [
    {'name': 'Michelangelo', 'food': 'PIZZA'},
    {'name': 'Garfield',   'food': 'lasanga'},
    {'name': 'Walter',    'food': 'pancakes'},
    {'name': 'Galactus',    'food': 'worlds'}
]

string = "Hi, I'm {} and I love to eat {}!"

def string_factory(thedicts, astring):
  alist = []
  for eachdict in thedicts:
    alist.append(string.format(eachdict['name'], eachdict['food']))
  return alist

print(string_factory(dicts, string))

2 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

There are two errors to fix:

  • use parameter name astring instead of "string" in alist.append() argument
  • add keywords to format argument list
def string_factory(thedicts, astring):
  alist = []
  for eachdict in thedicts:
    alist.append(astring.format(name=eachdict['name'], food=eachdict['food']))
  return alist