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Start your free trialBob Amand
2,639 PointsCounts.dy; can the key() values be converted to a list?
Is my strategy good? I attempted to convert the dictionary keys into a list of keys. Then I thought I could just count those that are equal to the list. Not working. I think I am missing a fundamental characteristic of the dictionary. Any clues would be helpful. Thanks.
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members(mydic,mylst):
count =0
inter = list(mydic.keys())
for i in mylst:
if i = inter[i]:
count += 1
return count
1 Answer
Kenneth Love
Treehouse Guest TeacherUltimately, you're doing an intersection. You want to see where these two items overlap. Your approach is OK (mydic.keys()
is already an iterable so you don't have to make it a list in order to be able to do a for
loop with it) but I see two things.
-
if i = inter[i]
is gonna fail because you can't do assignment in anif
-
if i in inter
would be a much better check because that tests whether or noti
is ininter
.