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Python Python Collections (Retired) Dictionaries Membership

dmitriy ignatiev
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.a{fill-rule:evenodd;}techdegree
dmitriy ignatiev
Python Web Development Techdegree Student 1,789 Points

counts.py

Hi,

please help. I have no idea why my function return 1 instead of 2 here's my code below.

def members(my_dict, my_list):
    count = 0
    for item in my_list:
        if item in my_dict:
            count += 1
            return count

# You can check for dictionary membership using the
# "key in dict" syntax from lists.

### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2

2 Answers

Vittorio Somaschini
Vittorio Somaschini
33,371 Points

Hello Dmitriy.

The problem here is the indentation of the return line. With the code you have written (I have edited the post so that it is properly formatted), the for statement only executes one and then returns the count straight away!

Try to think when you want to return the count, it should be the last thing to do, after all the cycles of the for statement.

Vitto