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Start your free trialstevejohnson2
5,165 PointsCreate a Fish object named $bass with the following data: name: "Largemouth Bass" flavor: "Excellent"
This question is vague, does anybody know what they are asking?
<?php
class Fish {
public $common_name;
public $flavor;
public $record_weight;
function Fish($name, $flavor, $record){
$this->common_name = $name;
$this->flavor = $flavor;
$this->record_weight = $record;
}
$bass = new fish(
$common_name = "Largemouth Bass";
$flavor = "Excellent";
$record_weight = "22 pounds 5 ounces";
);
}
?>
2 Answers
Julian Aramburu
11,368 PointsHi Steve! In that particular challenge you are supposed to use the constructor you just created to create a new instance of Fish. In this case the correct answer would be:
$bass = new Fish("Largemouth Bass", "Excellent", "22 pounds 5 ounces");
Since in the constructor you defined 3 parameter being name, flavor and record(weight).
Julian Aramburu
11,368 PointsCool I was able to help :)! Keep Coding!
stevejohnson2
5,165 Pointsstevejohnson2
5,165 PointsThanks very much Julian. Sorry about the delay in my response, I was busy doing a CSS track.