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942 PointsCreate a function named combo() that takes two iterables and returns a list of tuples. Each tuple should hold the first
I get the right result :[(1, 'a'), (2, 'b'), (3, 'c')] , but still say me wrong, that is the several times, I think they have bug in here. that is my code:
ist1 = [1,2,3]
string1 = 'abc'
def combo(list1,string1):
list_empty = []
for i in range(3):
tuple1 = list1[i],string1[i] # put each item in list1 and string1 into the tuple1
list_empty.append(tuple1) # let each tuple1 save into the list_empty
return list_empty
print(combo(list1,string1))
[MOD: added ```python formatting -cf]
2 Answers
Chris Freeman
Treehouse Moderator 68,441 PointsYour answer is very close. You are limiting the length of the iterables to three but you need to create a general solution. Adjusting the length of your range
to be based on the input should work.
ist1 = [1,2,3]
string1 = 'abc'
def combo(list1,string1):
list_empty = []
for i in range(len(list1)):
tuple1 = list1[i],string1[i] # put each item in list1 and string1 into the tuple1
list_empty.append(tuple1) # let each tuple1 save into the list_empty
return list_empty
print(combo(list1,string1))
hello lion
942 Pointsthank you telling me. Merry Christmas.