Create a function named most_classes that takes a dictionary of teachers. Each key is a teacher's name and their value i

Question

Create a function named most_classes that takes a dictionary of teachers. Each key is a teacher's name and their value is a list of classes they've taught. most_classes should return the teacher with the most classes.

I am stuck for more than a day now! Please help! Here is my code:

td = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'], 'Kenneth Love': ['Python Basics', 'Python Collections']}

def most_classes(td):

tempv = []
k = list(td.keys())  # <-- turning all keys in the dictionary into a new list -  k = []
v = list(td.values())# <-- turning all values in the dictionary into a new list - v = [[]], output is list within a list
i = len(v) # <-- defining the length of a sub_list

for sub_list in v: # <-- looping though sub_lists
    tempv.append(len(sub_list[0][i])) # <-- replacing names of subjects (values) with an int (just a number of subjects), 
                                      # <-- and turning it into a new list tempv = [] where numbers reflect number of subjects taught by each teachers
return k[tempv.index(max(tempv))] # <-- returning the corresponding index value in the teachers names (keys in dictionary)

Answer 1 · 2015-12-09T12:24:18Z

December 9, 2015 12:24pm

This should work here :

def num_teachers(my_dict):
    return(len(my_dict))

def most_classes(my_dict):
    max_count  = 0
    for key in my_dict:
        if len(my_dict[key]) > max_count:
            max_count = len(my_dict[key])
            answer = key
    return answer

Answer 2 · 2015-12-09T20:47:55Z

December 9, 2015 8:47pm

Great answer, this is an easier snippet of code to understand :

    def most_classes(teacher_dict):
      max_count = 0
      best_teacher = ''
      for teacher in teacher_dict:
        if len(teacher_dict[teacher]) > max_count:
               best_teacher = teacher
      return best_teacher

Answer 3 · 2016-11-19T05:55:51Z

November 19, 2016 5:55am

def most_classes(teacher_dict): max_count=0 max_teacher='' for teacher in teacher_dict: if len(teacher_dict[teacher])>max_count: max_count=len(teacher_dict[teacher]) max_teacher=teacher return max_teacher

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frankgusto

frankgusto

Create a function named most_classes that takes a dictionary of teachers. Each key is a teacher's name and their value i

3 Answers

Krzysztof Kucharzyk

Krzysztof Kucharzyk

Jeffery Briggette

Jeffery Briggette

hello lion

hello lion

David Leal

David Leal

rd. ln.

rd. ln.