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M aqeel
225 PointsCreate a New Float Variable named $floatOne with a value of 1.5. Without changing the value of $integerOne or $floatOne,
i can do this but error may be occur
<?php
//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$integerOne = $integerOne + 5;
$integerTwo = $integerTwo - 1;
$floatOne = 1.5;
$integerOne = 6;
var_dump($integerOne * $floatOne);
?>
2 Answers
pascal meers
6,508 PointsHi M aqeel,
You might want to try this. Explained in the comments in the file hope this helps you.
<?php
//Place your code below this comment
// the variables from task one
$integerOne = 1;
$integerTwo = 2;
// add 5 to the current value of $integerOne
$integerOne += 5;
// substract 1 from the current value of $integerTwo
$integerTwo -= 1;
// set the $floatOne variable to 1.5
$floatOne = 1.5;
/*make a new variable called $result
set that one to
$integerOne * $floatOne
*/
$result = $integerOne * $floatOne;
//Than echo out the result
echo "$result";
echo "<br />";
var_dump($integerOne);
echo "<br />";
var_dump($integerTwo);
?>
Garrett Kucinski
Full Stack JavaScript Techdegree Graduate 38,848 PointsAll you need is this
<?php
//Place your code below this comment
$integerOne = 1;
$integerTwo = 2;
$integerOne += 5;
$integerTwo -= 1;
$floatOne = 1.5;
echo $integerOne * $floatOne;