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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Posted by Vanessa Solymosi
Vanessa Solymosi
1,372 Points

Create an variable for the next exercice :-/

Create a function named returnValue that accepts a single argument (you can name it anything), then immediately returns that argument.

function returnValue(age) { return age; }

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter.

/* pleaaaase, I am blocked whith this code, what is the good code? */

function returnValue(age) { return age;

var echo = age; return returnValue('28'); }

script.js 
function returnValue(age) {
 return age;

  var echo = age;
  return returnValue('28');
}
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Kieran Barker
Kieran Barker
15,028 Points
Kieran Barker
Kieran Barker
15,028 Points

Hi, Vanessa! You’re so close!

Your first two lines are correct, but what you’ve then done is create a variable inside the function which would be equal to the age argument, but would never be returned. You are then trying to return a number as a result of calling the function which you are still declaring. Here’s what you needed to do:

// Create a function that accepts an argument and returns that argument
function returnValue(age) {
  return age;
}

// Outside the function declaration, call the function and assign it to a variable
var echo = returnValue(28);

I hope this makes sense! I should also point out that putting 28 in quotes, as you did, would make it a string and not an integer :)

Vanessa Solymosi
Vanessa Solymosi
1,372 Points
Vanessa Solymosi
Vanessa Solymosi
1,372 Points

Thanks a lot Kieran. One of my answers was that but I put it inside the {} :-/ I knew I had almost the good one but there was a little &/x@ #? stuff missing.