Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialMUZ141058 Loice Kajawu
3,364 Pointscreating an object
create a fish object named $bass with the following data name: "largemouth bass" flavor: "excellent" record: "22 pounds 5 ounces"
<?php
class Fish {
public $common_name;
public $flavor;
public $record_weight;
function __construct($name, $flavor, $record){
$this->common_name = $name;
$this->flavor = $flavor;
$this->record_weight = $record;
}
$mame = new fish();
$bass = new Fish("Largemouth Bass");
$flavor = new flavor("Excellent");
$record = new record("22 pounds 5 ounces");
}
?>
1 Answer
Robert Richey
Courses Plus Student 16,352 PointsHi Loice,
When a Fish object is created, the constructor is expecting three arguments.
Chris Shearon
Courses Plus Student 17,330 PointsChris Shearon
Courses Plus Student 17,330 PointsI'd like to add to what Robert said and include an example.
$bass = new Fish ( "Largemouth Bass" , "Excellent" , "22 pounds 4 ounces" );
Note how the order is the same as the constructor.